x+y+z = 9, x square + y square + z square = 35, find the value of x cube + y cube + z cube - 3 xyz
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14
It is your answer.
108
108
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Answered by
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(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz
81=35+2xy+2yz+2xz
xy+yz+zx=23
x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-xz-yz)
9(35-23)
9×12
108
81=35+2xy+2yz+2xz
xy+yz+zx=23
x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-xz-yz)
9(35-23)
9×12
108
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