Question

(x+y+z) /(x^2+y^2+z^2) ^(-1/2)​

Answer 1

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$( \frac{x + y + z }{ {x}^{2} + y {}^{2} + {z}^{2} } ) {}^{ - \frac{1}{2} } \\ \cancel{ ( \frac{ {x}^{2} + y {}^{2} + {z}^{2} }{x + y + z } )} {}^{ 2} \\ (x + y + z) {}^{2} = {x}^{2} + {y}^{2} + {z}^{2}$

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