Math, asked by saros2856, 9 months ago

x×(y+z)=x×y+x×z

x=-2/3,y=-4/6,z=-7/9​

Answers

Answered by aarongoyal
1

Answer:

Step-by-step explanation:

Which class question

Answered by sushanthalva57682
0

Answer:

Form a quadratic equation whose Roots are  x,y,z  

Now, let the equation be  ax3+bx2+cx+d=0  

So, Sum x+y+z=−b/a  

xy+yz+xz=c/a  

xyz=−d/a  

If  a=1 , equation will be  x3−6x2+15x−14=0  

So, x=2  is a root of equation : the equation can be written as  (x−2)(x2−4x+7)=0  

Since  x2−4x+7=0  has imaginary roots which are  2+isqrt3  and  2−isqrt3  

So, the only real solution for this equation is  x=2

2.

Step-by-step explanation:

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