Math, asked by vaibhav383, 1 year ago

x(y-z)+y(z-x)+z(x-y)

Answers

Answered by Anonymous
7
x(y-z)+y(z-x)+z(x-y)
=xy-xz+yz-xy+xz-yz
=0.

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Answered by vandanarajput
1
Hey friend here is the answer ☺️ _________________________
x(y-z) + y(z-x) + z(x-y)
After opening the bracket, we get
= xy - yz + yz - yx + zx - zy
= 0
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