Math, asked by KunalS91, 11 months ago

X=ylogxy then dy/dx=?

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Answered by Rakeshyv295

0

on diff....

0=y/xy(xy'+y) +log xy(y')

0=y'+y/x+y'.logxy

0=y'(1+logxy)+y/x

y'=-y/x(1+logxy)

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