Question

(x²+1)²-x²=0has which roots​

Answer 1

Answer:

please see below:

Step-by-step explanation:

(x^2+1) ^2=x^2

case1.

x^2+1 =+√x^2

=x

=> x^2 - x +1=0

=> x^2 -2* x*(1/2) +(1/2) ^2=-1+1/4

=>(x-1/2) ^2=-3/4

=> x=1/2+-√3i/2 Ans

case2. x^2+1 =+√x^2

=-x

=> x^2 +x +1=0

=> x^2 +2* x*(1/2) +(1/2) ^2=-1+1/4

=>(x+1/2) ^2=-3/4

=> x=-1/2+-√3i/2 ans.

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