Question

x² + 1/6x - 2
find the two zeros of the given polynomial. ​

Answer 1

Answer:

x2 + 1/6(x) – 2 = 0

6x2 + x – 12 = 0

6x2 – 8x + 9x – 12 = 0

(6x2 – 8x) + (9x – 12) = 0

2x(3x – 4) + 3(3x + 4) = 0

(3x – 4)(2x + 3) = 0

x = 4/3 or x = -3/2

Verification:

x2 + 1/6(x) – 2 = 0

x2 + (Sum of zeroes)(x) – (product of zeroes) = 0

Sum of zeroes = 4/3 – 3/2 = 1/6

Product of zeroes = 4/3 x (-3/2) = -2

Hence, verified.

Step-by-step explanation:

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