Math, asked by Sunstar50, 11 months ago

x²+1/x²=15 ; find x³-1/x³

Answers

Answered by Misquat

hey......
here is ur answer......

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Answered by ubb70

a^3-b^3 = (a-b)(a^2+ab+b^2)

x^3-1/x^3 => (x-1/x)(x^2+x*1/x+1/x^2)=0

=> {(x^2-1)/x}{x^2+1/x^2+1} =0
=> {(x^2-1)/x}{15+1} =0
=> {(x^2-1/x}[16] =0
=> (x^2-1)/x=0
=> x^2-1=0
=> x^2=1
=> X=1

Sunstar50: your answer is wrong

Sunstar50: Misquat's answer is correct and I've marked her answer as brainliest

ubb70: yes. my ans is wrong.

ubb70: thanks for comment

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