Question

x²+1/x²=2,find x-1/x​

Answer 1

Answer:

sorry I don't know your question clearly

Answer 2

$\huge\mathbb{\underline{\red{SOLUTION:-}}}$

$\mathtt{Given:- The \:value \:of x{}^{2}-\frac{1}{x}{}^{2}=2}$

●WE HAVE TO FIND THE VALUE OF:-

$\sf x-\frac{1}{x}$

$\sf formula\:used [x+\frac{1}{x}]{}^{2}\\ \\ \sf\implies x{}^{2}+\frac{1}{x}{}^{2}-2$

$\mathtt{\underline{\underline{\blue{According\:to\: question:-}}}}$

$\sf [x-\frac{1}{x}]{}^{2}=x{}^{2}+\frac{1}{x}{}^{2}-2\\ \\ \sf Given \:the\:value\:of\\ \\ \sf\implies x{}^{2}+\frac{1}{x}{}^{2}=2\\ \\ \sf Now\: put\:the\:value\\ \\ \sf (x-\frac{1}{x}){}^{2}=2-2\\ \\ \sf (x-\frac{1}{x}){}^{2}=0\\ \\ \sf\leadsto x-\frac{1}{x}=\sqrt{0}\\ \\ \sf\leadsto The \:value\:of x-\frac{1}{x}=0$

So the value:-

$\boxed{\underline{\red{\sf{x-\frac{1}{x}=0}}}}$

#BAL

#answerwithquality