Math, asked by shivamkumar956pa1z3n, 1 year ago

x2+1/x2=83findx3-1/x3

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Answered by yashodha
0
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Answered by Magnetron
0

 {x}^{2}  +  \frac{1}{ {x}^{2} }  = 83 \\  {x}^{2}  +  \frac{1}{ {x}^{2} }   -  2x \frac{1}{x}  = 83 - 2 \\  {(x -  \frac{1}{x}) }^{2}  = 81 \\ x -  \frac{1}{x}  =  +  - 9 \\    ( {x}^{3}  -   \frac{1}{ {x}^{3} } )  = (x -  \frac{1 }{x} )( {x}^{2}  +  \frac{1}{ {x}^{2} }  + 1) \\  =  +  - 9(83 + 1) =  +  - 756
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