Question

x²–10x+25=0,Find the roots of the given equation by the method of perfect square.

Answer 1

Here is ur answer buddy!

Answer 2

Solution :

Given Quadratic equation x²-10x+25=0

=> x² - 2*x*5 + 5² = 0

=> ( x - 5 )² = 0

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We know the algebraic identity,

a² - 2ab + b² = ( a - b )²

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=> ( x - 5 )( x - 5 ) = 0

Therefore

( x - 5 ) = 0 or x - 5 = 0

x = 5 or x = 5

Equal roots

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