Question

x2+12x-20/3x-5=x2+8x+12/2x+3
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Answer 1

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Find a relation?

•x²+12x-$\frac{20}{3x}$-5=x²+8x+$\frac{12}{2x}$+3

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→x²+12x-$\frac{20}{3x}$-5=x²+8x+$\frac{12}{2x}$+3

→$\cancel{x^2}$ +12x-8x-$\frac{20}{3x}$=$\cancel{x^2}$+$\frac{12}{2x}$+3+5

→4x-$\frac{20}{3x}$=$\frac{12}{2x}$+8

★Cross Multiply★

→$\frac{12x^{2}-20}{3x}$=$\frac{12+16x}{2x}$

★Cross Multiply LHS and RHS★

→(12x²-20)×2x=(12+16x)×3x

→24x³-40x=36x+48x²

→24x³-40x-36x-48x²

→24x³-76x-48x²

→2(12x³-24x²-38x)=0

→12x³-24x²-38x=0

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Answer 2

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