x²/16 + y²/81 =1 is symmetric about
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1
Solution
Given:
Equation of eclipse x²/16 + y²/81 =1
since, 81 > 16 the given eclipse is symmetric about Y axis.
From equation , we get,
a = 9 [a²= 81]
b = 4 [b² = 9]
c² = a² - b²
or, c² = 81 - 16
or, C = √65
Length of major axis , 2a = 18
Length of minor axis, 2 b = 8
Exentricity, e = c/a = √65 / 9
Answered by
8
AnswEr:-
Equation of eclipse x²/16 + y²/81 =1
As, 81 > 16 the given eclipse is symmetric about Y axis.
=> a = 9 [a²= 81]
=> b = 4 [b² = 9]
=> c² = a² - b²
=> c² = 81 - 16
=> C = √65
=> 2a = 18
=> 2 b = 8
Eccentricity, e = c/a = √65 / 9
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