Math, asked by shasonia46, 10 months ago

x²+16x-9=0
completing by square
method​

Answers

Answered by jay272
1

Answer:

x ^{2}  = 9 - 16x

x =  \sqrt{9 - 16x}

x = 3 - 4 \frac{1}{x}

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Answered by mahendrarajbhar83867
0

Answer:

Simplifying

x2 + 16x + -9 = 0

Reorder the terms:

-9 + 16x + x2 = 0

Solving

-9 + 16x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '9' to each side of the equation.

-9 + 16x + 9 + x2 = 0 + 9

Reorder the terms:

-9 + 9 + 16x + x2 = 0 + 9

Combine like terms: -9 + 9 = 0

0 + 16x + x2 = 0 + 9

16x + x2 = 0 + 9

Combine like terms: 0 + 9 = 9

16x + x2 = 9

The x term is 16x. Take half its coefficient (8).

Square it (64) and add it to both sides.

Add '64' to each side of the equation.

16x + 64 + x2 = 9 + 64

Reorder the terms:

64 + 16x + x2 = 9 + 64

Combine like terms: 9 + 64 = 73

64 + 16x + x2 = 73

Factor a perfect square on the left side:

(x + 8)(x + 8) = 73

Calculate the square root of the right side: 8.544003745

Break this problem into two subproblems by setting

(x + 8) equal to 8.544003745 and -8.544003745.

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