Question

x² +17/72x+1/72 pls help

Answer 1

${x}^{2} + \frac{17}{72} x + \frac{1}{72} = 0$
$= > 72 {x}^{2} + 17x + 1 = 0$
$= > 72 {x}^{2} + 8x + 9x + 1 = 0$
$= > (8x + 1)(9x + 1) = 0$
$so... \\ x = - \frac{1}{8} \\ or... \\ x = - \frac{1}{9}$