x²-2√5x+3... factorize.. solve it
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=x²-2√5x+3
=x²-2√5x+5-2
={(x)²-2(x)(√5)+(√5)²}-2 {(a-b)²=(a²-2ab+b²)}
=(x-√5)²-(√2)² {a²-b²=(a+b)(a-b)}
=(x-√5+√2)(x-√5-√2)
ITS DONE ;-)
=x²-2√5x+5-2
={(x)²-2(x)(√5)+(√5)²}-2 {(a-b)²=(a²-2ab+b²)}
=(x-√5)²-(√2)² {a²-b²=(a+b)(a-b)}
=(x-√5+√2)(x-√5-√2)
ITS DONE ;-)
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