Question

x² + 2 (m-1) x +(m+5) =0
i) real and distinct roots.
ii) equal roots.
iii) not real roots of​

Answer 1

Answer:

Solution :

Given equation is

<br> Comparing with

, we get a=1, b=2(m-1), c=m+5 <br> The equation will have two real and equal roots if <br> Discriminant (D)=0 <br>

<br> or

<br>

<br>

<br>

<br>

<br>

<br>

<br>

<br>

Hence, value (s) of m are -1 and 4.