Question

X2 -(2ab-1) x+(b2-b-20)

Answer 1

Answer:

hi I got only this much sorry......

Answer 2

Simplify:

Step-by-step explanation:

$\ Given \ value: \\\\x^2-(2ab-1)x+(b2-b-20)\\\\x^2-(2ab-1)x+b-20=0\\\ Solution: \\\\\ compare \ the \ value \ from \ ax^2+bx+c=0\\\\a= 1\\b= -(2ab-1) = (1-2ab)\\c=b-20\\\ formula: \\\\x= \frac{-b\± \sqrt{b^2-4ac}}{2a} \\\\x= \frac{-(1-2ab)\± \sqrt{(1-2ab)^2-4.1.(b-20)}}{2.1} \\\\x= \frac{-(1-2ab)\± \sqrt{(1+4a^2b^2-4ab-4b+80)}}{2} \\\\\ OR \ \ \ \ \ \\\\\ If \ the \given \ value \ is: \\\\ x2-(2ab-1)x+(b2-b-20)\\\\ \rightarrow x2-2axb+1x+b2-b-20\\\\ \rightarrow 3x-2axb+b-20$

$\rightarrow 3x-b(2ax-1)-20$

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