Question

x2 + 2x +1 = 0
solve this equation by using splitting the middle term..
fastly guys ... today is my test
in tution..​

Answer 1

x² +2x +1 = 0

x² + x+x + 1 = 0

x(x+1) +1(x+1) = 0

(x+1) (x+1) = 0

x = -1

Answer 2

Answer:

Factoring x2+2x+1

The first term is, x2 its coefficient is 1 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 1 • 1 = 1

Step-2 : Find two factors of 1 whose sum equals the coefficient of the middle term, which is 2 .

-1 + -1 = -2

1 + 1 = 2 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 1 and 1

x2 + 1x + 1x + 1

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x+1)

Add up the last 2 terms, pulling out common factors :

1 • (x+1)

Step-5 : Add up the four terms of step 4 :

(x+1) • (x+1)

Which is the desired factorization1.2 Multiply (x+1) by (x+1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+1) and the exponents are :

1 , as (x+1) is the same number as (x+1)1

and 1 , as (x+1) is the same number as (x+1)1

The product is therefore, (x+1)(1+1) = (x+1)2