x²-2x-8
Find zeroes of this polynomial and verify the relationship between zeros and coefficients.
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Answered by
5
Explanation:
x² - 2x - 8 = 0
x² -4x +2x -8 = 0
x (x - 4 ) + 2 (x - 4 ) = 0
(x-4) (x + 2) = 0
then (x - 4 ) = 0
x = + 4
x = 4
and (x + 2 ) = 0
x = - 2
values of x are " 4 " and " -2 "
Answered by
6
Hope it will help you
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