x²+2xy-y²=0 plz answer of this question
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Answered by
3
Step-by-step explanation:
x² + 2xy - y² = 0
=> (x - y)² = 0
=> x - y = 0 ( squaring both the sides )
=> x = y
Now, if we substitute the value x = y in the equation, we get,
x² + 2x × x - x² = 0
=> 2x² = 0
=>x² = 0
=> x = 0
Hence, x=0 and y=0
HOPE THIS HELPS
Answered by
0
Answer:
x={-2+√8}/2 and y = { - {√8 -2}+{1+{√2 -1}²}}/[2{√2 -1}²]
Step-by-step explanation:
put the values of x and y in the given situation.
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