X²+2xy + y²-a²+2 ab-f?
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Step-by-step explanation:
x^2+2xy+y^2-a^2+2ab-b^2
=(x^2+2xy+y^2)-(a^2–2ab+b^2)
=(x+y)^2-(a-b)^2
Applying identity (A^2 - B^2)=(A + B)(A - B)
=(x+y+a-b)(x+y-a+b)
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