Question

x² + 2xy = y2, then Dy
DX​

Answer 1

Answer:

x^2+2xy=y^2

x^2-y^2+2xy=(x-y)

Answer 2

x²+2xy= y²

2x+2y+2x•dy/dx = 2y•dy/dx

2x+2y = 2y•dy/dx - 2x•dy/dx

2x+2y = dy/dx ( 2y-2x)

Dy/dx = 2x+2y/2y-2x

= 2(X+y)/2(y-x)

dy/dx = X+y/y-x