Math, asked by Bhratesh, 1 year ago

x2/3+y2/3=a2/3 find dy/dx

Answers

Answered by vivek007146
5

 \frac{2}{3} \times  {x}^{\frac{2}{3}  -1 }  +  \frac{2}{3} y  {}^ { \frac{2}{3}  - 1} \frac{dy}{dx}  = 0 \\  \frac{2}{3} x {}^{ \frac{ - 1}{3} }  +  \frac{2}{3} y {}^{ \frac{ - 1}{3} }  \frac{dy}{dx}  = 0 \\ x {}^{ \frac{ - 1}{3} }  + y {}^{ \frac{ - 1}{3} }  \frac{dy}{dx}  = 0 \\ y {}^{ \frac{ - 1}{3} }  \frac{dy}{dx }  =  - x {}^{ \frac{ - 1}{3 } }  \\  \frac{dy}{dx }  =   \frac{ - x { \ }^{ \frac{ - 1}{3} } }{y {}^{ \frac{ - 1}{3} } }  \\  \frac{dy}{dx }  =   \frac{ - y {}^{ \frac{1}{3} } }{x {}^{ \frac{1}{3} } }
So here is your answer..VERY HAPPY TO HELP U..mark as brainliest
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