Question

x²-3x-1=0 solve by quadratic equation
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Answer 1

first compare the given equation by general form we get

a x square + bx + c=0

a

a=1,b=-3,c=-1

use foreigner method to solve it

then find value of b square - 4ac

we get value 13

then then use formula

x=-b±√b square - 4ac/2a

by putting the values of a b and c

we get x=3±√13/2

x=3+√13/2 or 3-√13/2 this is our final answer

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