Question

x² + 3x - 1 by completing square method​

Answer 1

Step-by-step explanation:

${x}^{2} + 3x - 1 = 0 \\ \\ {x}^{2} + 3x + \frac{9}{4} - 1 - \frac{9}{4} = 0 \\ \\ {(x + \frac{3}{2} )}^{2} - \frac{13}{4} = 0 \\ \\ {(x + \frac{3}{2} )}^{2} = \frac{13}{4}$