x2+3x+1=(x-2)2 find the quadratic equation
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2 +3x+1=(x−2)
2 +3x+1=(x−2) 2
2 +3x+1=(x−2) 2
2 +3x+1=(x−2) 2 x
2 +3x+1=(x−2) 2 x 2
2 +3x+1=(x−2) 2 x 2 +3x+1=x
2 +3x+1=(x−2) 2 x 2 +3x+1=x 2
2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4
2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x
2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2
2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2 +3x+1−x
2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2 +3x+1−x 2
2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2 +3x+1−x 2 +4x−4=0
2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2 +3x+1−x 2 +4x−4=0⇒7x−3=0 has its highest power 1
2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2 +3x+1−x 2 +4x−4=0⇒7x−3=0 has its highest power 1Hence it is not a quadratic equation.
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