Math, asked by deepak1137, 5 months ago

x2+3x+1=(x-2)2 find the quadratic equation​

Answers

Answered by Anonymous
5

Answer:

2

2 +3x+1=(x−2)

2 +3x+1=(x−2) 2

2 +3x+1=(x−2) 2

2 +3x+1=(x−2) 2 x

2 +3x+1=(x−2) 2 x 2

2 +3x+1=(x−2) 2 x 2 +3x+1=x

2 +3x+1=(x−2) 2 x 2 +3x+1=x 2

2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4

2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x

2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2

2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2 +3x+1−x

2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2 +3x+1−x 2

2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2 +3x+1−x 2 +4x−4=0

2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2 +3x+1−x 2 +4x−4=0⇒7x−3=0 has its highest power 1

2 +3x+1=(x−2) 2 x 2 +3x+1=x 2 −4x+4⇒x 2 +3x+1−x 2 +4x−4=0⇒7x−3=0 has its highest power 1Hence it is not a quadratic equation.

Step-by-step explanation:

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