Question

(x2 – 3x)2-8(x² – 3x) -20​

Answer 1

Answer:

$2(x {}^{2} - 3x) - 8(x {}^{2} - 3x) - 20 = 0$

$(x {}^{2} - 3x)(2 - 8) - 20 = 0$

$(x {}^{2} - 3x)( - 6) - 20 = 0$

$- 6x {}^{2} + 18x - 20 = 0$

dividing by -2.

$3x {}^{2} - 6x + 10 = 0$

by using shridacharya formula

$x = - b + - \sqrt{(b {}^{2} } - 4ac) \div 2a$

so x= {-(-6) + - √((-6)^2-4×3×10)}/2×3

x={6+-√(36-120)}/6

x={6+-√(-84)}/6

x={1+(√(84)i)/6}. x={1-(√84)i/6}

Two answers and i= iota .