Math, asked by rajkaran89, 9 months ago

x²+3x-70=0 solve the qradratic equation​

Answers

Answered by guptaamitjj
2

Answer:

Step-by-step explanation:

(-b±√b^2-4ac)/2a

a=1

b=3

c=-70

[-3±√3^2-4*1*(-70)]/2*1

[-3±√9-(-280)]/2

[-3±√9+280]/2

[-3±√289]/2

(-3±17)/2

1. -20/2=-10

2.14/2=7

x=-10 or 7

Answered by jitendrakumar42015
0

Answer:

The values of x are x_{1} = -10, x_{2} = 7

Step-by-step explanation:

We can solve this question bt quadratic formula x=-b\pm \sqrt{b^{2} -4ac}

We have given the equation x^{2} +3x-70=0

As we can see the equation here, a=1, b=3,c=-70, Putting all these value of a,b and c in quadratic formula

 x=-3\pm\sqrt{3^{2}-(4\times1\times-70) } \times \dfrac{1}{2}

x=-3\pm\sqrt{9-(-280)} \times \dfrac{1}{2}

x=-3\pm\sqrt{9+280} \times \dfrac{1}{2}

x=-3\pm\sqrt{289} \times \dfrac{1}{2}

x_{1}=(-3-17)\times \dfrac{1}{2} = -10

x_{2}=(-3+17)\times \dfrac{1}{2} = 7

Similar questions