(x2+3x-xb-3b)\(x+3) divide using factorisation
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Answered by
18
(x^2 +3x - xb- 3b )/(x+3)
= ( x ( x +3) - b ( x +3))/( x+3)
= ((x +3)(x-b ))/(x +3)
= ( x- b) ans
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= ( x ( x +3) - b ( x +3))/( x+3)
= ((x +3)(x-b ))/(x +3)
= ( x- b) ans
pls mark it as brainliest
Answered by
3
Answer:
Step-by-step explanation:
First of all group them like this-
[(x^2+3x)-(xb-3b)]/(x+3)
Now Take out all the commons and rearrange-
[x(x+3)-b(x+3)/(x+3)
(x+3)(x-b)/(x+3)
now cutout (x+3) because they are gonna divide and (x-b) will remain
Therefore answer is (x-b)
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