Question

x2-4x+4=0 determine the following nature of the roots of the quadratic equations from their discriminates m2+2m+0=0​

Answer 1

Answer:

real and equal

Step-by-step explanation:

To find the nature of roots, use formula

$b^{2} - 4ac$

Here a = 1, b = -4, c = 4

$= {( - 4)}^{2} - (4 \times 1 \times 4)$

$= 16 - 16 = 0$

b² - 4ac = 0

So, the nature of the roots is real and equal.

Verification:

by factorisation,

${x}^{2} - 4x + 4 = 0$

$(x - 2)(x - 2) = 0$

x = 2, 2 which is real and equal

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