Question

X2-4x+5 find the zeroes of a polynomial​

Answer 1

To Find:-

$\tt \blue { \: Zeroes \: of \: \: \: (x^2 \: -4x \: + \: 5) }$

Solution:-

Finding zeroes by the method of Quadratic Formula.

First finding discriminant.

$\tt \large\bf \: \red{D=b^2-4ac} \: \\ \tt = {( - 4)}^{2} - 4(5) \\ = 16 - 20 \\ = - 4$

Here the value of D is less than Zero.

So, no real roots are possible.

Check the Question again .

Formula that will be used:-

$\tt \dfrac{ - b + \sqrt{D} }{2a} \: \: and \: \dfrac{ - b - \sqrt{D} }{2a}$

Points to Notice:-

• No real roots are possible if the Discriminant is less than zero.
• The following Questions can also be answered by factorisation method and completing square method.
• Every Quadratic Equation has two Zeroes.