Question

x²-4x+a= 0 has no real roots find a
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Answer 1

Answer:

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Answer 2

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$\longrightarrow \: {x}^{2} - 4x + a = 0$

• It has no real roots ..

• It means Discriminant must be negative (smaller than zero)

• D < 0

In this equation ,

A = 1

B = -4

C = a

D = B² - 4AC

D = (-4)² - 4×1×a

D = 16 - 4a

As , D < 0

so,

16 - 4a < 0

16 < 4a

4 < a

a > 4

• a is greater than 4 ,
• it means a belongs to (4 , infinity)