Question

X2+4x2+6 has no zero
N0 zero.

Answer 1

Answer:

✅Here's your answer

${x}^{2} + 4 {x}^{2} + 6 \\ \\ 5 {x}^{2} + 6$

Here a =5 ,b = 0 and c=6

D= b^2 - 4 ac

D= 0-120

D=-120

✔Therefore, The given equation has no real roots...

Hope it helps ✌