x²+4y²-z²-4xy factorise
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Answered by
25
x² + 4y² – z² – 4xy
= (x² + 4y² – 4xy) – z²
= (x – 2y)² – z²
= (x – 2y + z)(x – 2y – z)
Answered by
5
x²-4xy+4y²-z²=0
(x-2y)²-z²=0
(x-2y-z =0)( x-2y+z=0)
(x-2y)²-z²=0
(x-2y-z =0)( x-2y+z=0)
bhupendra6:
wrong
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