x²+5x–1=0,Solve the given equation using the general formula.
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Solution :
Compare given Quadratic equation
x²+5x-1=0 with ax²+bx+c=0, we get
a = 1 , b = 5 , c = -1
Discreminant ( D ) = b² - 4ac
= 5² - 4 × 1 × ( -1 )
= 25 + 4
D = 29
*************************************
We know the quadratic formula :
x = [ -b ± √D ]/( 2a )
************************************
x = [ -5 ± √29 ]/2
•••••
Compare given Quadratic equation
x²+5x-1=0 with ax²+bx+c=0, we get
a = 1 , b = 5 , c = -1
Discreminant ( D ) = b² - 4ac
= 5² - 4 × 1 × ( -1 )
= 25 + 4
D = 29
*************************************
We know the quadratic formula :
x = [ -b ± √D ]/( 2a )
************************************
x = [ -5 ± √29 ]/2
•••••
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