Question

-X2+5x-4>0 slove for x

Answer 1

-x² + 5x - 4 > 0

→ x² - 5x + 4 < 0

→ x² - x - 4x + 4 < 0

→ x(x - 1) - 4(x - 1) < 0

→ (x - 4)(x - 1) < 0

→ x ∈ (1 , 4) ___________(Ans.)

Hence, x belongs to the set (1 , 4)

Hope it helps....

^______°

Answer 2

Answer:

-x² + 5x - 4 > 0

Now , Comparing with ax² + bx + c = 0 we got,

a = -1 , b = 5 , c = -4

Discriminant = b² - 4ac

= 5² - 4 × -1 × -4

= 25 - 16

= 9

Now Roots = - b + √D ÷ 2a

or -b - √D ÷ 2a

= -5 + √9/-2

or

= -5 - √9/-2

= -2/-2 = 1

or

= -8/-2 = 4

So , x = 1 or 4 Answer..........