(x²-5x+6)-(x²-6x+8)²
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Hi friend!!
Given,
(x²-5x+6)-(x²-6x+8)²
=(x²-2x-3x+6)-(x²-4x-2x+8)²
=(x(x-2)-3(x-2))-(x(x-4)-2(x-4))²
=(x-2)(x-3)-[(x-2)(x-4)]²
=(x-2)[(x-3)-(x-2)(x-4)²]
=(x-2)[(x-3)-(x-2)(x²+16-8x)]
=(x-2)(x-3-x³-16x+8x²+2x²+32-16x)
=(x-2)(-x³+10x²-31x+29)
I hope this will help you ;)
Given,
(x²-5x+6)-(x²-6x+8)²
=(x²-2x-3x+6)-(x²-4x-2x+8)²
=(x(x-2)-3(x-2))-(x(x-4)-2(x-4))²
=(x-2)(x-3)-[(x-2)(x-4)]²
=(x-2)[(x-3)-(x-2)(x-4)²]
=(x-2)[(x-3)-(x-2)(x²+16-8x)]
=(x-2)(x-3-x³-16x+8x²+2x²+32-16x)
=(x-2)(-x³+10x²-31x+29)
I hope this will help you ;)
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