x2-6x=0one of the root of the quadratic equation
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Answer:
x2-6x=0one
Step-by-step explanation:
Let the roots of the first and second equations are (α,4β) and (α,3β) respectively
∴ product of the roots are 4αβ=a ....(1)
and 3αβ=6⇒αβ=2
⇒a=8 . ....From eqn (1)
Therefore, the roots of the equation x
2
−6x+8=0 are (2,4).
Given that the other roots of the first and second equations are integers, so if α=4⇒β=
2
1
In this case 3β is not integer.
Therefore, common root will be α=2
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