Question

x2-6x=0y2-5y+6=0 are the four sides for a? ​

Answer 1

Answer:

(0,2),(0 3),(6,2),(6,3) are Vertices and Area odlf square is 6.

then what are the vertices correct? don't worrybwe can solve it. I understood your question. and here we go be resolving.

two equations above can be resolved for two xs and two ys

x= 0, 6

y= 2,3

now equations of four sides are x=0 and x= 6 and y= 2 and y=3.

this is bounded Square.