Question

X2-6X+5 quadratic polynomial s and verify the relationship between the zeros and the cofficients​

Answer 1

Answer:

Step-by-step explanation:

x  ^2  +5x+6=0

x^  2 +2x+3x+6=0

x(x+2)+3(x+3)=0

(x+2)(x+3)=0

x=−2,−3

∴α=−2,β=−3

α+β=−  b/a

​ −2−3=−  5/1  

​ −5=−5

αβ= c/a

(−2)(−3)=  6/1

​6=6