x²+6x+5
solve by split method
Answers
Answered by
3
hii mate✋✋
_______
here is ur answer ⤵⤵⤵
→x²+6x+5
→ x²+5x+1x+5
→ x(x+5)+1(x+5)
→ (x+1)(x+5)
values of "x" are
⤵⤵⤵⤵⤵⤵⤵
→x=(-1)✔
&&&&&
→ x=(-5)✔✔
_________
⭐hope it helps uh⭐
_______
here is ur answer ⤵⤵⤵
→x²+6x+5
→ x²+5x+1x+5
→ x(x+5)+1(x+5)
→ (x+1)(x+5)
values of "x" are
⤵⤵⤵⤵⤵⤵⤵
→x=(-1)✔
&&&&&
→ x=(-5)✔✔
_________
⭐hope it helps uh⭐
Ajay1291:
beautiful awesome answer sneha
Answered by
3
If you have a quadratic function
a
x
2
+
b
x
+
c
, to factorise it you should identify two numbers whose product is
a
c
and sum is
b
.
Here in
y
=
x
2
−
6
x
+
5
, we should identify two numbers whose product is
5
and sum is
−
6
.
Such numbers are
−
5
and
−
1
and now splitting middle term into these we get
y
=
x
2
−
5
x
−
x
+
5
or
y
=
x
(
x
−
5
)
−
1
(
x
−
5
)
=
(
x
−
1
)
(
x
−
5
)
.
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