Question

x2+6x+7=0 completing square method

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

1 and -7

Step-by-step explanation:

x2+6x+7=0

x2+6x+9-9-7=0

x2+3x+3x+9=16

x(x+3)+3(x+3)=16

(x+3) (x+3)=16

(x+3)2=(4)2

x+3=4

2*a*b=6x

2*x*b =6x. (a=x)

b=6x/2x

b=3

b2=9

Taking square root on both the sides

Half of cofficient of x= 6/2= 3

if x+ 3 =4. if x+3=4

x =4-2. x= -4-3

x=1. x= -7

1 and -7 are the root of x2+6x-7=0