Question

x²+6x-8=0 completing square method​

Answer 1

$x = 2 \: and \: 4$

$solve.$

$x^{2} - 6x + 8 = 0$

$factor.$

$(x - 2)(x - 4) = 0$

$solve \: for \: x.$

$x - 2 = 0$

$x = 2$

$x - 4 = 0$

$x = 4$

$x = 2 \: and \: 4$

graph{y=x^2-6x+8 [-10, 10, -5, 5]}