Math, asked by CodmicAbhishek9933, 1 year ago

X²-6x+9 factorisation by suitable identities

Answers

Answered by Anonymous

10

Answer:

Step-by-step explanation:

x^2-3x-3x+9=0

x(x-3)-3(x-3)=0

(x-3)(x-3)=0

x=3

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