Question

x²+6x-(a²+2a-8)=0 factorization ​

Answer 1

Answer:

(x+2-a)(x-4-a)

Step-by-step explanation:

x²+6x-(a²+2a-8)

solve it by using the equation x=(-b±√(b²-4ac))/2a

a=1, b=6, c=a²+2a-8

x = (-6±√(36 - 4(a² + 2a - 8))) / 2

x= (-6±√4(9-a²+2a-8)) / 2 = (-6 ±2√-a²+2a+1) / 2

x= -3 ± √(1-a)² = -3± 1 - a

we have x = -3+1-a,-3-1-a = 2-a, -4-a

it can be written as (x+2-a), (x-4-a)