-x²+6x³-3- 10x divided by 2x-3
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Answer:
Quotient = 3x² + 4x - 7
Remainder = 0
Step-by-step explanation:
Divide the polynomial (6x³ + 11x² - 10x - 7) by the binomial (2x + 1). Write the quotient and the remainder.
6x³ + 11x² - 10x - 7
= 6x³ + 3x² + 8x² + 4x - 14x - 7 + 0
= 3x²(2x + 1) + 4x(2x + 1) - 7(2x + 1) + 0
= (3x² + 4x - 7)(2x+1) + 0
((6x³ + 11x² - 10x - 7)/(2x + 1)
= ((3x² + 4x - 7)(2x+1) + 0) / (2x + 1)
Cancelling 2x + 1 from numerator & denominator
= 3x² + 4x - 7
Quotient = 3x² + 4x - 7
Remainder = 0
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