Question

x²-6xy+x²,Find the value of the given polynomial by taking x = 1, y = 3 and a = 2.

Answer 1

Hey there!

$Given,\\x = 1, y =3,a =2\\\\x^2 - 6xy + x^2\\=1^2 - 6\times 1\times 3 + 1^2\\=1 -18 + 1\\=\boxed{\boxed{\bold{-16}}}$

Hope It Helps YoU!

Answer 2

$\textbf {Hey there, here is the solution.}$

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x²- 6xy + x

.

Given x = 1 , y = 3 and a = 2

x²- 6xy + x

= (1)²- 6(1)(3) + (1)

= 1 - 18 + 1

= -16

.

Answer : -16

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⭐$\textbf {Cheers}$⭐