x²-7x+12=0 find the equation
Answers
Answered by
6
x^2-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-4) (x-3) = 0
x=4 , x= 3
x(x-4)-3(x-4)=0
(x-4) (x-3) = 0
x=4 , x= 3
Answered by
2
x^2-7x+12=0
x^2-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-4)(x-3)=0
x=4 or x=3
HOPE IT HELPS YOU:__
x^2-4x-3x+12=0
x(x-4)-3(x-4)=0
(x-4)(x-3)=0
x=4 or x=3
HOPE IT HELPS YOU:__
Similar questions