Question

X2-7x+3=0 for two decimel place qerratic equation

Answer 1

Step-by-step explanation:

a = 1

b = -7

c = 3

x(1) = (-b² + √b² - 4ac) / 2a

x(1) = (-(-7)² + √(-7)² - (4) (1) (3)) / (2)(1)

x(1) = (7² + √49 - 12) /2

x(1) = (49 + √37) /2

x(1) = (49 + 6.0827625303)/2

x(1) = 55.0827625303/2

x(1) = 27.54138126515

x(1) = 27.54

x(2) = (-b² - √b² - 4ac) / 2a

x(2) = (-(-7)² - √(-7)² - (4) (1) (3)) / (2)(1)

x(2) = (7² - √49 - 12) /2

x(2) = (49 - √37) /2

x(2) = (49 - 6.0827625303)/2

x(2) = 42.9172374697/2

x(2) = 21.45861873485

x(2) = 21.46

Roots are 27.54 and 21.46